C and Cpp Programming

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Answer:- C

📌Scope resolution (::) operator is used to access the variable which is outside the scope.

📌 ::a-!a++ is evaluated as 10 - 0
(!a++ is evaluated as 0, since there ! operator)

📌 Hence we got 10 as the output.

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Answer: 10 40

📌  ptr = &a; (pointer ptr starts to point 'a')
ptr = &b; (now pointer ptr starts to point 'b')

📌 *ptr = *ptr+*ptr;
This statement is equal to 

b = 20 + 20 (since ptr points to b therefore *ptr = b)

📌 Hence we get "10 40" as the output.

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